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Mademuasel [1]
3 years ago
15

In measuring the center of the data from a skewed distribution, the median would be preferred over the mean for most purposes be

cause:
Mathematics
1 answer:
icang [17]3 years ago
5 0
<span>The median would be preferred over the mean in such scenarios because the median will lessen the impact of the outliers that fall within the "tail" of the skew. Therefore, if a curve is normally distributed, that is to say that data is normally distributed, there will be two tails, each with approximately equal proportions of outliers. Outliers in this case being more extreme numbers, and are based on your determination depending on how you are using the data. If data is skewed there is one tail, and therefore it may be an inaccurate measure of central tendency if you use the mean of the numbers. Thinking of this visually. In positively skewed data where there is a "tail" towards the right and a "peak" towards the left, the median will be placed more in the "peak", whereas the mean will be placed more towards the "tail", making it a poorer measure of central tendency, or the center of the data.</span>
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If(x)= 2e^x-1 +3 , what is f^-1 (x)
Rainbow [258]

Answer:

f^-1 (x) =  1+ln( (x-3)/2)

Step-by-step explanation:

hello :

let f(x) = y  so : y = 2e^(x-1) +3

calculate x :  e^(x-1) = (y-3)/2

for : y-3 > 0 :  x-1 = ln( (y-3)/2)    so : x= 1+ln( (y-3)/2)

If(x)= 2e^(x-1) +3 , what is f^-1 (x) =  1+ln( (x-3)/2)

4 0
3 years ago
A baseball team has 15 field players and 10 pitchers. Each field player can take any of the 8 non-pitching positions. What is th
leonid [27]

Answer:

If order matters: 2,594,592,000 ways.

If order does not matter:  64,350 ways

Step-by-step explanation:

Assuming that the order matters when picking the non-pitching positions (since they are different positions), the number of possible different starting lineups is given by the permutation of picking 8 players out of 15, multiplied by 10 (pick one out of 10 pitchers):

n =10*\frac{15!}{(15-8)!}\\ n=10*15*14*13*12*11*10*9*8\\n=2,594,592,000

Now if the order of the field players is not important, the number of possible starting lineups is given by the combination of picking 8 players out 15, multiplied by 10:

n = n =10*\frac{15!}{(15-8)!8!}\\ n=\frac{10*15*14*13*12*11*10*9*8}{8*7*6*5*4*3*2} \\n=64,350

Therefore, the number of ways to pick the starting lineup is:

If order matters: 2,594,592,000 ways.

If order does not matter:  64,350 ways

7 0
3 years ago
Saby used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables b
Degger [83]
Short Answers
P(Both) = 0.1792
Givens
The total number of roles = 100
Total number of heads = 56
Number of times rolled a four =  32 [check this for me].

Set up the probabilities.
P(H) = 56/100
P(4) = 32/100
P(H)*P(4) = P(Both)

Substitute and solve
P(Both) = 56/100 * 32/100 = 1792/10000
P(Both) = 112/625 because there are many cancellations. Or you could just express it as 0.1972

8 0
3 years ago
You bake 42 chocolate cupcakes and 28 red velvet cupcakes.You package them in boxes that have the same ratio of chocolate to red
blondinia [14]

Answer: 16 red velvet cupcakes.

Step-by-step explanation:

To solve this problem you can apply the following proccedure:

- Let's call the number of red velvet cupcakes in a box that has 24 chocolate cupcakes: x

- Based on the information given in the problem, you can set up the following proportion and Solve for x<em>:</em>

\frac{42}{28}=\frac{24}{x}\\\\1.5x=24\\x=16

There are 16 red velvet cupcakes in a box that has 24 chocolate cupcakes.

5 0
3 years ago
Andy estimated that he would need 79 feet of lumber for a tree house project. He later found that the actual amount of lumber ne
Radda [10]

Answer:

Step-by-step explanation:

79 divided by 68 is your answer

You can do the math

5 0
3 years ago
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