We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
Step-by-step explanation:
Line is passing through the points:
Equation of line in two point form is given as:
which of the following group of numbers are all prime numbers a.2,5,15,19 b.7,17,29,49 c.3,11,23,31 d.2,3,5,9,
antoniya [11.8K]
Prime numbers are those that cannot be divided by another number (other than themselves and 1). In other words, prime numbers have factors of themselves and 1.
For example, 3 is a prime number because its only factors are 3 and 1.
6 is not a prime number because it can be factored to 3*2.
Therefore, the correct answer is c. 3,11,23,31
Answer:
A,B,C,D
Step-by-step explanation:
I say all of them because all of them are spelled correctly but if it incorrect i'm very sorry
