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Ugo [173]
3 years ago
13

PLEASE HELP WILL MARK BRAINLIEST Problem Page Question In a recent year, 36% of all college students were enrolled part-time. If

6.8 million college students were enrolled part-time that year, what was the total number of college students? Round your answer to the nearest million.
Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0
I’m not exactly sure but i think it is around four million
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Original price: $0.75<br> Discount:?<br> Sale price: $0.15
Masteriza [31]

Answer:

80% off

Step-by-step explanation:

(0.15 - 0.75)/0.75 = -0.8 = -80%

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2 years ago
Evaluate and write test answer in simplest and proper form :3/5÷2 /3
Tpy6a [65]

Answer:

Exact form: 9/10 , Decimal form: 0.9

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3 years ago
Gabe​ Amodeo, a nuclear​ physicist, needs 60liters of a 40%acid solution. He currently has a 30 % solution and a 60% solution. H
Alecsey [184]
39.5 I think that's the answer I hope its right if wrong than I'm truly srry
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3 years ago
If for two non-zero vectors a,b : ∣a+b∣=∣a−b∣ then angle between them is:______a. 0b. 45c. 60d. 90
Eddi Din [679]

Answer:

90^\circ

Step-by-step explanation:

Given two non zero vectors, \vec a, \vec b.

Let the angle between the two vectors = \theta

Given that:

|\vec a+\vec b|=|\vec a-\vec b|

Let us have a look at the formula for magnitude of addition of two vectors:

|\vec x+\vec y|=\sqrt{x^2+y^2+2xycos\theta}

Where \theta is the angle between the two vectors.

formula for magnitude of subtraction of two vectors:

|\vec x-\vec y|=\sqrt{x^2+y^2-2xycos\theta}

As per the given condition:

\sqrt{a^2+b^2+2abcos\theta}=\sqrt{a^2+b^2-2abcos\theta}

Squaring both sides:

a^2+b^2+2abcos\theta=a^2+b^2-2abcos\theta\\\Rightarrow 2abcos\theta=-2abcos\theta\\\Rightarrow cos\theta = -cos\theta\\\Rightarrow 2cos\theta = 0\\\Rightarrow cos\theta = 0\\\Rightarrow \theta = 90^\circ

So, the angle between the two vectors is: 90^\circ

7 0
2 years ago
Statements Reasons 1. BE || CD 1. Given 2. ∠A ≅ ∠A 2. Reflexive Property 3. ∠ACD ≅ ∠ABE 3. Corresponding angles formed by parall
Leno4ka [110]

Answer:

The correct option is;

C) AA Similarity Postulate

Step-by-step explanation:

The given parameters are;

BE║CD Given

∠A is congruent to ∠A Reflective property

∠ACD is congruent to ∠ABE Corresponding angles formed by parallel lines and a transversal

∠ADC is congruent to ∠AEB Corresponding angles formed by parallel lines and a transversal

ΔABE ~ ΔACD AA Similarity Postulate

When two angles of one triangle are equal to the corresponding two angles of another triangle, given that the third angle of both triangles are also equivalent based on sum of angles of a triangle postulate, the two triangles are said to be similar based on Angle-Angle (AA) Similarity Postulate.

6 0
3 years ago
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