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3 years ago

Plot connect the points to make picture. Please

Mathematics

1 answer:

mixas84 [53]3 years ago

5 0

Answer:

that is what it would look like

Hope it helps!❤❤

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SWAN85 help please please

fenix001 [56]

Answer:

first y=|x+6|

y=2x+7,y=2x-7 parallel lines

Step-by-step explanation:

first y=|x+6|

y=2x+7,y=2x-7 parallel lines

5 0

4 years ago

What is the approximate distance between points A and B?

Klio2033 [76]

Answer: 7.62

Step-by-step explanation:

$AB=\sqrt{(-2-1)^{2}+(-3-4)^{2}}=\sqrt{9+49}=\sqrt{58} \approx 7.62$

7 0

2 years ago

What is the surface area of the cube below?

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

because one side surface area is 8x8=64, and there is 6 sides so 64x6 = 384 units2

6 0

4 years ago

Read 2 more answers

Find the mean of first five prime<br> numbers

gtnhenbr [62]

Answer:

5.6

Step-by-step explanation:

(2+3+5+7+11)/5

=5.6

7 0

3 years ago

22. An employee joined a company in 2017 with a starting salary of $50,000. Every year this employee receives a raise of $1000 p

Setler79 [48]

Answer:

(a) The recurrence relation for the salary is

$S_{n+1}=1.05*S_n+1000\\\\S_0=50000$

(b) The salary 25 years after 2017 will be $217044.85.

Step-by-step explanation:

We can define the next year salary $S_{n+1}$ as

$S_{n+1}=S_n+1000+0.05*S_n=1.05*S_n+1000$

wit S0=$50000

If we extend this to 2 years from 2017 (n+2), we have

$S_{n+2}=1.05*S_{n+1}+1000=1.05*(1.05*S_n+1000)+1000\\S_{n+2} =1.05^2*S_n+1.05*1000+1000\\S_{n+2}=1.05^2*S_n+1000*(1.05^1+1)$

Extending to 3 years (n+3)

$S_{n+3}=1.05*S_{n+2}+1000=1.05(1.05^2*S_n+1000*(1.05^1+1))+1000\\\\S_{n+3}=1.05^3S_n+1.05*1000*(1.05^1+1)+1000\\\\S_{n+3}=1.05^3*S_n+1000*(1.05^2+1.05^1+1)$

Extending to 4 years (n+4)

$S_{n+4}=1.05*S_{n+3}+1000=1.05*(1.05^3*S_n+1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1.05*1000*(1.05^2+1.05^1+1))+1000\\\\S_{n+4}=1.05^4S_n+1000*(1.05^3+1.05^2+1.05^1+1.05^0)$

We can now express a general equation for S_n (salary at n years from 2017)

$S_n=1.05^nS_0+1000*\sum_{0}^{n-1}1.05^n$

The salary at 25 years from 2017 (n=25) will be

$S_{25}=1.05^{25}S_0+1000*\sum_{0}^{24}1.05^i\\\\S_{25}=3.386*50000+1000*47.72=217044.85$

8 0

4 years ago