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2 years ago

11

Which inequality describes all the solutions to 5(3 − x) < −2x + 6?

1 answer:

Marrrta [24]2 years ago

4 0

Given:

The inequality is

$5(3-x)$

To find:

The inequality that solution describes all the solutions to the given inequality.

Solution:

We have,

$5(3-x)$

Using distributive property, we get

$5(3)+5(-x)$

$15-5x$

$15-6$

$9$

Divide both sides by 3.

$\dfrac{9}{3}$

$3$

It can be written as

$x>3$

Therefore, the value of x is greater than 3. So, the required inequality is either $x>3$ or $3$ .

You might be interested in

To simplify5(2x-7) use distributive property

sveta [45]

Answer:

10×-35

Step-by-step explanation:

5×2=10

5×7=35

So the answer is 10x-35

8 0

2 years ago

Without graphing classify each system as independent dependent or inconsistent -x -y=7<br> 5x-5y=5

jek_recluse [69]

Answer:

Is a consistent independent system

Step-by-step explanation:

we have

$-x-y=7$ -----> isolate the variable y

$y=-x-7$ ----> equation A

$5x-5y=5$ -----> isolate the variable y

$y=x-5$ ---> equation B

Compare equation A and equation B

We can affirm that

The slopes are not equal ( so the lines are not parallel)

The lines are different

The product of their slopes is equal to -1 (the lines are perpendicular)

so

The system of equations has only one solution

therefore

Is a consistent independent system

5 0

2 years ago

1/5 x = 12 plz help im not very good with math

IceJOKER [234]

Answer:

Step-by-step explanation:

1/5x = 12

x = 12 × 5

x = 60

( By using transposing method )

Plz mark it as brainliest

You can recheck it by calculating

60/5= 12

5 0

2 years ago

Read 2 more answers

If f(x) = 7x − 1, what does f(12) represent?

Rasek [7]

Hello :
f(12) represent : <span>B. The value of (7x − 1) when x = 12</span>

7 0

2 years ago

Read 2 more answers

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

6.

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

7 0

2 years ago