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3 years ago

8

What's the distance between theses two. (-5, 1) (2, 4)

1 answer:

ludmilkaskok [199]3 years ago

6 0

Answer: squareroot of 58

You can solve this problem simply by using the <u>distance formula .</u> Using the distance formula we can solve this problem by just placing the numbers and then solving the equation.

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The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago

Is the point (5,-1) a solution of y=2x-11

Nataly [62]

if the given point satisfies this equation then it would be its solution

(-1)=2(5)-11

-1=10-1

-1=-1

lHS=RHS

Hence (/,-1) is the solution of y=2x-11

3 0

3 years ago

Donna was playing a trivia game where you gained points for correct answers and lost points for incorrect answers. At the start

yanalaym [24]

Step-by-step explanation:

B 100

7 0

3 years ago

Read 2 more answers

Just help me out with this polynomial i need help <br> { -m^{2} + 6} + { -4m^{2} + 7m + 2} =

PolarNik [594]

Answer:

$-5m^2+7m+8$

Step-by-step explanation:

Here, we add up two polynomials shown.

The polynomials are:

$[-m^2 + 6]+[-4m^2 +7m + 2]$

In order to add up the 2 polynomials shown, we have to see the "like terms" and add them up.

We add up the " $m^2$ " terms and the constant (number) terms. There is one term with "m", so we leave it like that. Let's add up. Shown below:\

$[-m^2 + 6]+[-4m^2 +7m + 2]\\=-m^2-4m^2+6+2+7m\\=-5m^2+7m+8$

This is the sum of the 2 polynomials shown: $-5m^2+7m+8$

7 0

3 years ago

Find the value of the variable 10 45

Ratling [72]

Answer:

35.

Step-by-step explanation:

3 0

3 years ago