Question

Use addition to solve the linear system of equations. Include all of your work in your final answer. \(\left\{ \right.\) 3x-y=6 y=x-4

Answer 1

Answer:

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

Step-by-step explanation:

We need to solve the linear system of equations.

$3x-y=6 \\y=x-4$

We can write second equation y=x-4  as: $-x+y=-4$

Let:

$3x-y=6--eq(1)\\ -x+y=-4--eq(2)$

Now, Adding equation 1 and 2

$3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1$

So, we get x = 1

Now, put value of x in second equation to find value of y:

$y=x-4\\Put\:x=1\\y=1-4\\y=-3$

So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)