$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
Find the slope of the line passing throught the points (2, 2) and (4, 3).
The formula of a slope:

Substitute:

If the point (x, -1) lie on the same line, then the slope of line passing through the points (2, 2) and (x, -1) the same:
Substitute:

We have the equation:
<em>cross multiply</em>

<em>add 2 to both sides</em>

<h3>Answer: x = -4.</h3>
We have

Plug in

:

⇒

So we now have

Plug in

:

⇒

⇒
![b=\sqrt[3]{\frac{95}{4}}](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D)
which is approximately 2.874
So we get
![y=4(\sqrt[3]{\frac{95}{4}})^{x}](https://tex.z-dn.net/?f=y%3D4%28%5Csqrt%5B3%5D%7B%5Cfrac%7B95%7D%7B4%7D%7D%29%5E%7Bx%7D)
or, in decimal form,