Answer: Yes.
Step-by-step explanation: Plug in your values. Does y=16 when x=4? 16 = 3(4) +4, which equals 16, so yes.
To get which design would have maximum area we need to evaluate the area for Tyler's design. Given that the design is square, let the length= xft, width=(120-x)
thus:
area will be:
P(x)=x(120-x)
P(x)=120x-x²
For maximum area P'(x)=0
P'(x)=120-2x=0
thus
x=60 ft
thus for maximum area x=60 ft
thus the area will be:
Area=60×60=3600 ft²
Thus we conclude that Tyler's design is the largest. Thus:
the answer is:
<span>Tyler’s design would give the larger garden because the area would be 3,600 ft2. </span>
Answer: (-20,-4)
First, you substitute y into the first equation to get 0.01x - 0.3(0.1x - 2) = 1
You then distribute the 0.3 to what is inside the parentheses to get 0.01x-0.03x+0.6=1
(Note: the 0.6 is positive because two negatives multiplied equal a positive)
Now you combine like terms to get -0.02x+0.6=1
Subtract 0.6 from both sides of the equal sign to get -0.02x=0.4
Divide each side by -0.02 to get x=-20
Now plug in -20 to y=0.1x-2 to get y=-4
This gives you the answer (-20,-4)
Answer:
Option 4: 1.25/2π = 32/2πr
Step-by-step explanation:
Arc length = (theta/2pi) × 2pi × r
32 = (1.25/2pi) × 2pi × r
1.25/2pi = 32/(2pi × r)
