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tigry1 [53]
3 years ago
13

Kingsley then adds 49.28 mL of NaOH to 250.00 mL of the HCOOH solution. The neutralization reaction resulted in 0.098 moles of H

COOH and 0.025 moles of HCOO left in solution. Determine the pH of the resulting solution. Which of the following acids would produce the highest pH at the equivalence point in a weak acid-strong base titration?
Ka(HF) =6.8x10-4
Ka(HNO2) =4.5x10-4
Ka(HCIO2) =1.1x10-2
K(CH3COOH) =1.8x10-5
i. HCIO2
ii. CH3COOH
iii. HF
iv. HNO2
Chemistry
1 answer:
vladimir2022 [97]3 years ago
6 0

Answer:

i. HCIO2 - 2.9

ii. CH3COOH - 2.64

iii. HF - 3.27

iv. HNO2 - 2.67

Explanation:

The Ph value differ for base and acid. A neutral solution will have Ph value of 7. For acid the Ph value is less than 7 and for base Ph value is greater than 7. The highest Ph value for the given acids is 3.27 for hydroflouric acids.

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A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculated the molar enthalpy change
MrRa [10]

Answer:

-54 kJ/mol

Explanation:

Given that:

A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculated the molar enthalpy change of the acid-base neutralization reaction to be –54 kJ/mol

i.e

50 ml of 1.0 M HCl +  50 ml of 1.0 M NaOH -----> -54 kJ/mol

If he repeat the same experiment with :

100 ml of 1.0 M HCl + 100 ml of 1.0 M NaOH. ------> ????

From The experiment; the molar enthalpy of change of the acid-base neutralization reaction will be -54 kJ/mol

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Similarly; we can assume that :

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SO; when he used 100 ml ;

then the amount of moles used is double, likewise the heat liberated will be doubled ;

So;

2P moles is used to liberate 2Q kJ heat ;

2P/2Q = Q/P ( kJ/mol) = -54 kJ/mol

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3 years ago
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