Ca=40
N=14
O=16
Ca=40
N=14x2=28
O=6x16=96
molar mass=40+28+96
molar mass=164g/mol
Answer is: <span>mass of calcium carbonate needed is 120 grams.
</span>Chemical reaction:
CaCO₃(s) → CaO(s) + CO₂(g)<span>.
</span>V(CO₂) = 27.0 L.
Vm = 22.4 L/mol.
n(CO₂) = V(CO₂) ÷ Vm.
n(CO₂) = 27 L ÷ 22.4 L/mol.
n(CO₂) = 1.2 mol.
From chemical reaction: n(CO₂) : n(CaCO₃) = 1 : 1.
m(CaCO₃) = 1.2 mol.
m(CaCO₃) = n(CaCO₃) · M(CaCO₃).
m(CaCO₃) = 1.2 mol · 100 g/mol.
m(CaCO₃) = 120 g.
Answer: When the temperature of an object increases, the average kinetic energy of its particles increases. When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increases.
Explanation: Hope this helps!!
Answer:
71g (assuming experimental data)
Explanation:
The balanced equation for this reaction:
+
→
+ 
Molar mass of H2SO4 = 98.1 g/mol
molar mass of NaOH = 40g/mol
Molar mass of Na2SO4 = 142.04g/mol
⇒ 1 mole or 98.1g of H2SO4 will yield 1 ole of NaSO4; alternately, 2 moles or 49 ×2 = 80g of NaOH produces 1 mole of NaSO4.
<em>Therefore, limiting reactant is NaOH.</em>
Assuming actual experiment is 20g of NaOH,
1 mole - 40g
x moles - 20g =
= 0.5 moles
⇒1 mole of Na2SO4 - 142.04g
∴ 0.5 moles = 142.04 × 0.5
<u>= 71.02g</u>
Answer:
WHat the heck happened to ur question umm sir?!
Explanation: