Question

Need cos A and tan A asap please

Answer 1

Answer:

$\sin A=\frac{12}{37},\\\\\cos A=\frac{35}{37},\\\\\tan A=\frac{12}{35}$

Step-by-step explanation:

In a right triangle only, the sine of an angle is equal to the angle's opposite side divided by the hypotenuse of the triangle. (o/h)

The cosine of the angle is equal to the angle's adjacent side divided by the hypotenuse of the triangle. (a/h)

The tangent of the angle is equal to angle's opposite side divided by the adjacent side. (o/a)

In this case, angle A's opposite side is 12, its adjacent side is 35, and the hypotenuse is 37 (o=12, a=35, h=37).

Thus we have:

$\sin A=\frac{12}{37},\\\\\cos A=\frac{35}{37},\\\\\tan A=\frac{12}{35}$

Answer 2

Answer:

Step-by-step explanation:

sin A=opposite/hypotenuse=12/37

cos A=adjacent/hypotenuse=35/37

tan A=opposite/adjacent=12/35