Answer:
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Step-by-step explanation:
Answer:
The fifth degree Taylor polynomial of g(x) is increasing around x=-1
Step-by-step explanation:
Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

and when you do its derivative:
1) the constant term renders zero,
2) the following term (term of order 1, the linear term) renders:
since the derivative of (x+1) is one,
3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero
Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is:
as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1
For any point reflected in the y- axis
(x, y ) → (- x, y )
A(1, 1) → A'(- 1, 1)
B(5, 1 ) → B'(- 5, 1 )
C(3, 3 ) → C'(- 3, 3 )
3x-2-(2x+1)= 3x-2-2x-1
= x- 3
C. x - 3
Answer:
one solution
Step-by-step explanation:
intersecting lines always have one solution.