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Marina86 [1]
3 years ago
11

Which of the following ordered pairs are a solution for the equation y = 6x − 3?

Mathematics
1 answer:
storchak [24]3 years ago
5 0

Answer:

-1,9

Step-by-step explanation:

I got them wrong so it showed me the right answer

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Ivanna paid $11.88 for a 2.38-pound bag of shrimp at one store. The following week, she paid $26.47 for a 5.08-pound bag at anot
stepan [7]

Answer:

2.38 lb bag = 4.99/lb   5.08 lb bag = 5.21/lb  The 2.38 is the better buy

Step-by-step explanation:

1.88/2.38 = 4.99

26.47/5.08 = 5.21

4.99 is cheaper than 5.21 so the 2.38 lb bag is better buy

8 0
2 years ago
Read 2 more answers
-10 F is colder than -4 degrees?
Aleks04 [339]

Answer: yes, it is a smaller temperature, which means that is "colder"

Step-by-step explanation:

I guess that the question is:

Is -10°F colder than - 4°C?

Ok, when we have a temperature T in Celcius, the equation to transform this quantity to the Fahrenheit scale is:

T' = (T*9/5) + 32°

Replacing T by the temperature in celcius, we get:

T' = (-4°*9/5) + 32° = 24.8°F

This means that -4°C is equivalent to 24.8°F

And -10°F is a smaller value than 24.8°F (which mean that is colder)

This implies that -10°F is colder than -4°C

Then the statement is true.

4 0
3 years ago
Determine whether the graphs of y=-7x-4 and -y=7x+4 are parallel, perpendicular, coincident or none of these
horsena [70]

we are given

y=-7x-4

-y=7x+4

we can multiply -1 on both sides of second equation

-1*-y=-1(7x+4)

y=-7x-4

we can see that

both equations becomes same

so, they are coincident............Answer

5 0
2 years ago
Read 2 more answers
Please help !!
shutvik [7]

Given:

The limit problem is:

\lim_{x\to 3}(x^2+8x-2)

To find:

The limit of the function by using direct substitution.

Solution:

We have,

\lim_{x\to 3}(x^2+8x-2)

Applying limit, we get

\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2

\lim_{x\to 3}(x^2+8x-2)=9+24-2

\lim_{x\to 3}(x^2+8x-2)=33-2

\lim_{x\to 3}(x^2+8x-2)=31

Therefore, the correct option is D.

4 0
3 years ago
A grading machine can grade 48 tests in 1 minute. How
S_A_V [24]
\bf \begin{array}{ccll}
tests&minutes\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
48&1\\
300&m
\end{array}\implies \cfrac{48}{300}=\cfrac{1}{m}\implies m=\cfrac{300\cdot 1}{48}
3 0
3 years ago
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