Answer:
96360
Step-by-step explanation:
search hours a month then multiply that by 12
The length and width that will maximize the area are 175 ft and 87.5 ft respectively
The largest area that can be enclosed is 15312.5 ft²
<h3>Area of a rectangle</h3>
where
l = length
w = width
The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.
Therefore,
perimeter = l + 2w
350 = l + 2w
l = 350 - 2w
area = (350 - 2w)w
(350 - 2w)w = 0
where
w = 0 or 175
average = 175/2 = 87.5
Hence, the max area is at w = 87.5 ft
Therefore,
l = 350 - 2(87.5) = 175 ft
length = 175 ft
width = 87.5 ft
Therefore,
area = 175 × 87.5 = 15312.5 ft²
Therefore, the largest area that can be enclosed is 15312.5 ft²
learn more on rectangle here: brainly.com/question/11630499
Compute the slope of the line through (-2, -9) and (-4, -17):
Any line perpendicular to this line will have slope -1/4. The one that passes through (0, 10) satisifes
Answer:
<u>(-7,-3)</u>
Step-by-step explanation:
step one) solve one equation for x.
y=-3x
-3x/-3=y/-3
x=(-y/3)
step two) plug in x for the other original problem.
y=x-4
y=(-y/3)-4
step three) solve for y.
y=(-y/3)-4
y+4=(-y/3)-4+4
3*(y+4)=(-y/3)*3
3y+12=-y
(3y+12)-3y=-y-3y
12/-4=-4y/-4
y=-3
step four) plug in -3 for y and solve for x.
y=x-4
-3=x+4
-3-4=x+4-4
-7=x
<em>I am in algebra two so you can trust my answer. if you need more help lmk in the comments. happy holidays and stay safe!</em>
