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Ymorist [56]
3 years ago
13

F(x) = 3x^2 -3x -7 How many real roots does f(x) have? Explain using the determinant.

Mathematics
1 answer:
balandron [24]3 years ago
7 0
Answer is : 1.2
Step Equation
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The path a character takes to navigate a level of a video game is given in the following graph.
mylen [45]

The domain is the set of x values that has a corresponding y-values in a function or a graph.

The domain of the graph is: -10 \le x \le 10

From the graph (see attachment), we have the following observation

  • The value of x starts from -10 (represented by the horizontal line from (-10,4) to (-4,4))
  • The value x ends at 10 (represented by the slant line on the first quadrant)

These values can be represented as:

x_1= -10

x_2 = 10

So, the domain of x is: -10 \le x \le 10

Read more about domain at:

brainly.com/question/24302079

4 0
3 years ago
What percent of 150 is 9?
irga5000 [103]
One of the ways to find the answer is to find how much 1 percent of 150 is. To do that we just have to divide 150 by 100:

150 / 100 = 1.5

Now we can divide 9 by 1.5 to know how much percent of 150 it is:

9 / 1.5 = 6

Let's check it:

150 * 6% = 150 * 6/100 = 15 * 6/10 = 3 * 6/2 = 18/2 = 9

It's correct then :)
3 0
3 years ago
An apartment building has the following apartments:
artcher [175]
On the second floor we have 6 apartments, and we have 2 more apartments with 3 bedrooms, so 8/16 apartments are either on the second floor or have 3 bedrooms. 8/16 is the same as 1/2, or 50%
3 0
3 years ago
What is the repulsive force between two pith balls that are 13.0 cm apart and have equal charges of −24.0 nC?
daser333 [38]

Answer:

The repulsive force is 3.067\times10^{-4}N.

Step-by-step explanation:

Consider the provided information.

The coulomb's law to calculate the repulsive force: F=\frac{kQ_1Q_2}{r^2}

Where the value of k is 9.00×10⁹ Nm²/C²

Substitute the respective values in the above formula.

F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{[(13 cm)(\frac{1m}{100cm} )]^2}

F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{(0.13 m)^2}

F\approx0.0003067N

F=3.067\times10^{-4}N

Hence, the repulsive force is 3.067\times10^{-4}N.

8 0
3 years ago
How much does a person owes me at the end off 55 months if was supposed to pay me 1000.00 per months at 12 % per month?
Solnce55 [7]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
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