Since the first equation already gives you y, substitute Y for 4x in the second equation.
y=4x
x+y=5
x+(4x)=5
5x=5
x=1
Now that you know x, plug in x for 1 in the first equation.
y=4(1)
y=4
Answer: (1,4)
Answer:
4 and 12
Step-by-step explanation:
a = young
b = old
b = 3a, a+b =2a+8 => a = 4, b = 12
Answer and explanation:
Answer:
Two sample t test
Explanation:
The test that could be used here is the two sample t test. The two sample t test compares two groups to ascertain if there is an average significant different between the two groups being compared, also making sure the result of difference is not random. For instance to test the above example, the two sample t test compares the group before they watch the commercial with the group after the commercial to know if there is a significant difference between the two groups.
Hi Kimberly!
-(19 - 3s) - (8s + 1) = 35
-19 + 3s -8s - 1 = 35
-19 - 1 + 3s - 8s = 35
-20 - 5s = 35
-5s =35 + 20
-5s = 55
Divide both sides by -5
-5s/-5 = 55/-5
s = -11
A+ for Algebra guaranteed! <span />
Answer:
-6i
Step-by-step explanation:
Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.
If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.
x + 8 = 0
x = -8
x - 1 = 0
x = 1
x^2 + 36 = 0
x^2 = -36 ... take the square root of both sides to get x alone
x = √-36 ... square root of an imaginary number produces the usual square root and an "i"
x = ±6i
