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3 years ago

Implicit differentiation using dy/dx

Mathematics

1 answer:

Anarel [89]3 years ago

8 0

Is it possible for there to be a No Solution?

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Why do you get a math error when you try to evaluate (-100) ^0.5, but not when you evaluate -100^1.5?

Angelina_Jolie [31]

The parentheses take part in that

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4 years ago

The line with gradient-4 which cuts the y axis at -2

Helen [10]

Answer:

• Considering the general equation of a line

$y = mx + b$

m is the gradient and b is the y-intercept.

Substitute:

${ \underline{ \underline{ \: \: y = - 4x - 2 \: \: }}}$

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3 years ago

Prove algebraically that (m + 2)2 – m 2 – 12 is always a multiple of 4

Julli [10]

Answer:

$(m + 2)^{2} - m^{2} - 12 = 4(m - 2)$

Step-by-step explanation:

Step 1:

Write the expression

$(m+2)^{2} - m^{2} - 12$

Step 2: Expand $(m + 2)^{2}$

$(m+2)^{2} - m^{2} - 12\\(m+2)(m+2) - m^{2} - 12\\m^{2} + 2m + 2m + 4 - m^{2} - 12$

Step 3: Collect similar terms

$m^{2} - m^{2} + 4m + 4 - 12\\4m - 8$

Step 4: Factor 4 out of the expression to prove that the expression is a multiple of 4.

$Therefore\\4m - 8 = 4(m - 2)\\Hence,\\(m+2)^{2} - m^{2} - 12 is a multiply of 4 because the expression is equal to 4(m-2)$

3 0

3 years ago

Can someone help me pls thanks

allsm [11]

Answer:

x = 1/2QN^2

Step-by-step explanation:

8 0

3 years ago

Choose the correct word that completes each statement about inscribing a square in a circle.

Anna11 [10]

Answer:

1. Perpendicular

2. Isosceles

3. Never

Step-by-step explanation:

1. AC ⊥ BD because diameter of a square are perpendicular bisector of each other.

2. In Δ AOB , By using pythagoras : AB² = OA² + OB² .......( 1 )

In Δ COB , By using pythagoras : BC² = OC² + OB² ..........( 2 )

But, OA = OC because both are radius of same circle

So, by using equations ( 1 ) and ( 2 ), We get AB = BC ≠ AC

⇒ ABC is a triangle having two equal sides so ABC is an isosceles triangle.

3. The side can never be equal to radius of circle because the side of the square will be chord for the circle and in a circle chord can never be equal to its radius

7 0

3 years ago