Answer:
4
Step-by-step explanation:
the figures are
0,0,3,8,1,0
we repeat 0
so we have 4 figures,
0,3,8,1
Let's begin by listing the first few multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44. So, between 1 and 37 there are 9 such multiples: {4, 8, 12, 16, 20, 24, 28, 32, 36}. Note that 4 divided into 36 is 9.
Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:
<span>How many multiples of 4 are there in {n; 37< n <101}? We could list and then count them: {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval. Try subtracting 40 from 100; we get 60. Dividing 60 by 4, we get 15, which is 1 less than 16. So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:
1000
-40
-------
960
Dividing this by 4, we get 240. Adding 1, we get 241.
Finally, subtract 9 from 241: We get 232.
There are 232 multiples of 4 between 37 and 1001.
Can you think of a more straightforward method of determining this number? </span>
Step-by-step explanation:
1. 1/13 2. 1/26
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And
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To find the y-intercept of any equation just need to put 0 (( zero )) instead of the x in the equation...
<h2>
Let's do it....</h2>
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In f ( x ) :
Thus :
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In g ( x ) :
Thus :
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The positive difference in the y-intercept value of f ( x ) and g ( x ) is :
So write this in the box : 1
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And we're done....
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2700 is the answer. You do 9 times 3 then add the 0s
