A) one game shall be completed as it says. although if the game is sped up you may have a chance to have more or if it is slowed down not even one game!
b) i really have no clue to show a model but yes that is what i think i know im dumb and its emo logic but yea...
The solution would be like this for this specific problem:
Volume of a cylinder = pi * r^2 * h
Volume of a cone = 1/3 * pi * r^2 * h
Total Height = 47
Height of the cone = 12
Height of the cylinder = 35
If the top half is filled with sand, then:
volume (sand) = pi * 4^2 * 36
volume (cone) = 1/3 * pi * 4^2 * 12
Total volume = 1960.353816 cubic millimeters
353816 / (10 * pi) = 62.4 seconds.
It will take 62.4 seconds until all of the sand has dripped to the bottom of the hourglass.
First we write it into scientific notation which is 3.5*10^7. now it's order of magnitude is power of 10 that is 7. So order is 7.
The answer is: x = 7 - √53 or x = 7 + √53
The general quadratic equation is: ax² + bx + c =
0.
But, by completing the square we turn it into: a(x + d)² + e = 0, where:<span>
d = b/2a
e = c - b²/4a
Our quadratic equation is x² - 14x -4 = 0, which is
after rearrangement:
So, a = 1, b = -14, c = -4
Let's first calculate d and e:
d = b/2a = -14/2*1 = -14/2 = -7
e = c - b²/4a = -4 - (-14)</span>²/4*1 = -4 - 196/4 = -4 - 49 = -53<span>
By completing the square we have:
a(x + d)² + e = 0
1(x + (-7))</span>² + (-53) = 0
(x - 7)² - 53 = 0
(x - 7)² = 53
x - 7 = +/-√53
x = 7 +/- √53
Therefore, the solutions are:
x = 7 - √53
or
x = 7 + √53
The equilateral triangles will form a rhombus.
