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Ivan
3 years ago
12

Please help me on this will give you brainliest!

Mathematics
2 answers:
kirill [66]3 years ago
8 0

Answer:

∠V = 33°

∠W = 90°

∠X = 57°

Step-by-step explanation:

In a right triangle, the sum of the acute angles is 90 degrees

(2x+3) + (3x+12) = 90

combine like terms

5x + 15 = 90

5x = 75

x = 15

∠V = 2x+3, x=15

2(15) + 3

30 + 3

33°

∠X = 3x+12, x=15

3(15) + 12

45 + 12

57°

SashulF [63]3 years ago
5 0
The guy above pretty much answered it
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8 0
3 years ago
What is the equation of the oblique asymptote?<br> h(x) = x² – 3x - 4/x + 2
NNADVOKAT [17]

Simplifying h(x) gives

h(x) = (x² - 3x - 4) / (x + 2)

h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)

h(x) = ((x + 2)² - 7x - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)

h(x) = (x + 2) - 7 - 22/(x + 2)

h(x) = x - 5 - 22/(x + 2)

An oblique asymptote of h(x) is a linear function p(x) = ax + b such that

\displaystyle \lim_{x\to\pm\infty} h(x) - p(x) = 0

In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.

4 0
2 years ago
Can u plz help me look at the photo<br><br> PLZ NO LINKS
djyliett [7]

Answer:

0.07

Step-by-step explanation:

The hundredths place is the place between the tenths and thousandths place. For example, the digit in the tenths place in 0.073 is 7.

To round to the nearest hundredth, we look to the digit right of the hundredth digit, 7. We notice that the digit in the thousandths place is 3. When rounding, if a number is 4 or less, we change that digit to a 0, along with the digits beyond it. If a number is 5 or more, we bump up the digit to the next number. Since 3 is less than 4, we change 0.073 to 0.07.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

8 0
2 years ago
It took my question down twice here's a real math question I guess
aliina [53]

Answer:

n-3

Interval notation: (-\infty, -10)\cup(-3,\infty)

Step-by-step explanation:

<u>First inequality:</u>

<u />n+8

Therefore, this inequality restricts:

n \in \mathrm{R};\: n

<u>Second inequality:</u>

< 8+n-3

Therefore, this inequality restricts:

n \in \mathrm{R};\: n>-3

Therefore, with both of these restrictions together, we have:

\fbox{$n \in \mathrm{R}; n-3$}\\\mathrm{or\:}\fbox{$n-3$}\\\mathrm{or\:}\fbox{$(-\infty, -10)\cup(-3,\infty)$}.

4 0
3 years ago
How do you do this? with work.
Rashid [163]

Answer:

i don't know

Step-by-step explanation:

so i have 20 the answer i thin

7 0
3 years ago
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