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3 years ago

To prove that DEF congruent DGF by SAS,what additional information is needed

Mathematics

2 answers:

lisabon 2012 [21]3 years ago

8 0

Answer:

∠DFE ≅ ∠DFG

Step-by-step explanation:

we know that

Triangles are congruent by SAS, if any pair of corresponding sides and their included angles are equal in both triangles

In this problem we have that

The pair of corresponding sides that are equal are

EF=GF and DF (is the same side for both triangles)

The included angle are ∠DFE and ∠DFG

therefore

The additional information needed to prove that triangles DEF and DGF are congruent by SAS is that angles ∠DFE and ∠DFG are equal

∠DFE ≅ ∠DFG

kompoz [17]3 years ago

7 0

Answer:de=dg

Step-by-step explanation:

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An agency has 4,000 employees. 2,000 employees have at least two years of college education. 1,000 of those employees have bache

weqwewe [10]

Answer:

1/80 of the agency's employees have PhDs.

Step-by-step explanation:

Given that:

Total number of employees = 4000

Number of employees with bachelors degree = 1000

Fraction of employees with graduate degree = 1/4 of 1000 = 250

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2 years ago

If sine theta equals three over four, what are the values of cos θ and tan θ?

ratelena [41]

Answer:

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus three over root seven

Step-by-step explanation:

Given that sin ∅ =3/4 It means the ratio of the opposite side to the hypotenuse side is 3:4.

Using the Pythagoras theorem we can calculate the hypotenuse adjacent as follows.

a²+b²=c²

a²=c²-b²

a²=4²-3²

a²=16-9

a²=7

a=√7

Then Cos ∅= opposite/ adjacent

=√7/4

Then Tan ∅ = opposite/adjacent

=3/√7

In words, Cosine theta equals plus or minus square root of seven over 4,tangent theta equals plus or minus three over root seven.

7 0

3 years ago

Can someone help me with this?

Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

$Sum = \frac{a( {r}^{n} - 1) }{(r - 1)} \\$

So,

$\frac{a( {r}^{n} - 1)}{(r - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{(3 - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{2} = 728 \\ {3}^{n} - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n} = 729 \\ {3}^{n} = {3}^{6} \\ \boxed{ n = 6}$

Therefore, number of terms is 6

6 is the right answer.

3 0

3 years ago