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serg [7]
3 years ago
15

Solve the problem. If sin = 1/4, find csc . A) 3/4 B) -1/4 C) 4 D) undefined

Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0

Answer:

C) 4

Step-by-step explanation:

By definition, cosecant (csc) is the reciprocal of sine (sin). The reciprocal of 1/4 is equal to C) 4.

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james has for four and three forths feet of rope he plans to cut off one and a half feet from the rope how much will rope be lef
mamaluj [8]
The answer is 3 and one forth i'm pretty sure 
4 0
3 years ago
Why are 4(5) and 20 equivalent expressions?
Studentka2010 [4]

Answer:

4 times 5 = 20, and 20 is... well.. 20

Step-by-step explanation:

When a number has another number in parentheses by it, it means you multiply the numbers together. So 4(5) is the same as 4 times 5, which equals 20

5 0
3 years ago
Read 2 more answers
Koran showed 0.08 w/ the model below.
kumpel [21]
The model shown is equal to 0.8, not 0.08.

She needs to only have 8 of the little boxes shaded.

Glad I could help, and good luck!
__________________________
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6 0
3 years ago
Read 2 more answers
Mr. Jones purchased two sodas.
kondaur [170]

Answer:

  the prices were $0.05 and $1.05

Step-by-step explanation:

Let 'a' and 'b' represent the costs of the two sodas. The given relations are ...

  a + b = 1.10 . . . . the total cost of the sodas was $1.10

  a - b = 1.00 . . . . one soda costs $1.00 more than the other one

__

Adding these two equations, we get ...

  2a = 2.10

  a = 1.05 . . . . . divide by 2

  1.05 -b = 1.00 . . . . . substitute for a in the second equation

  1.05 -1.00 = b = 0.05 . . . add b-1 to both sides

The prices of the two sodas were $0.05 and $1.05.

_____

<em>Additional comment</em>

This is a "sum and difference" problem, in which you are given the sum and the difference of two values. As we have seen here, <em>the larger value is half the sum of the sum and difference</em>: a = (1+1.10)/2 = 1.05. If we were to subtract one equation from the other, we would find <em>the smaller value is half the difference of the sum and difference</em>: b = (1.05 -1.00)/2 = 0.05.

This result is the general solution to sum and difference problems.

5 0
3 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
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