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3 years ago

The diameter of a circle is 6 centimeters. Calculate the circumference of the circle.

Mathematics

1 answer:

artcher [175]3 years ago

7 0

Answer:

2πr

Step-by-step explanation:

Figure out the radius by halfing the diameter which will be 3. Then, use the formula to solve the question.

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Which expression is equivalent to 9a + 12?

Veronika [31]

Answer:

3(3a+4)

Step-by-step explanation:

3(3a+4)

use distributive property

9a+12

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3 years ago

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a square pyramid has a height of 14 cm and a base side length of 7 cm. What is the volume of the pyramid. Show work

Brut [27]

Step-by-step explanation:

The volume of a pyramid or cone is:

V = ⅓ Ah

where A is the area of the base and h is the height.

The pyramid has a square base, so:

A = s²

A = (7 cm)²

A = 49 cm²

The height is 14 cm, so the volume is:

V = ⅓ (49 cm²) (14 cm)

V = 686/3 cm³

V ≈ 228.67 cm³

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3 years ago

ILL GIVE BRAINLIEST 1 x/3 - 3/4= 5/12 solve for x

mel-nik [20]

X/3 - 3/4 = 5/2
x/3 = 3.25
x= 9.75 Or 9 3/4

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2 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

Find the area of the figure ABC

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

Find the area of the semicircle

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

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3 years ago

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3 years ago

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