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bagirrra123 [75]
3 years ago
12

How are you expose to solve 7n-7n=1

Mathematics
1 answer:
eduard3 years ago
6 0

You just subtract normally because they both have the same variable. I hope you find this helpful.

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The value of x in the expression<br> 2x/3 - 7 = 5 is
Andrej [43]

Answer:

The answer is X = 18

Step-by-step explanation:

2x/3 - 7 = 5

Multiply both sides if the equation by 3 : 2x - 21 = 15

Move the constant to the right hand side and change its sign : 2x = 15 + 21

Calculate 2x = 15 + 21

2x = 36

Divide both sides of the eqaution by 2 : 2x = 36

x = 18

Answer X = 18

3 0
3 years ago
What is the surface area of a square pyraimd that is 5.95cm long and 5.1 cm wide
nydimaria [60]
I believe that the answer to this question is 30.345 cm

4 0
3 years ago
Find the probability of rolling a 6 on a number cube and flipping heads on a coin
serious [3.7K]

Assuming that the number cube is 6 sided

6 is one number in a 6 sided cube, so the probability is: 1/6

heads is one side of the coin, with two in all: 1/2

Multiply the two fractions together

1/6 x 1/2 = 1/12

1/12 is your probability

hope this helps

4 0
3 years ago
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I need help in these questions please !​
timama [110]

Answer:

b,b.a

Step-by-step explanation:

6 0
2 years ago
A cylindrical roller with diameter 77 cm and height 1 m is used to level a rectangular park with dimensions22 × 11 . Find the nu
Vlad [161]

Answer:  The number of revolutions required to level the park is 100.

Step-by-step explanation:

Given : Diameter of roller = 77 cm

Then radius of roller : r = \dfrac{77}{2}\ cm

Height = 1 m = 100 cm

Curved surface area of roller = 2\pi rh= 2\times\dfrac{22}{7}\times\dfrac{77}{2}\times100=24200\ cm^2

Dimensions of park = 22 × 11 m

Then Area of park = 22\times11\ m^2= 232\ m^2=232\times100\times100 \ cm^2

=2420000\ cm^2

Now , the number of revolutions required to level the park = (Area of park) ÷ (Curved surface area of roller )

2420000\div 24200=100

Hence, the number of revolutions required to level the park is 100.

7 0
3 years ago
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