Step-by-step explanation:
I'm sorry that i cannot answer your question but i need these points badly for my questions for some missing assignments i have sorry
Answer:
![\frac{1}{45}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B45%7D)
Step-by-step explanation:
We have been given that a jar is filled with 7 red marbles and 3 green marbles. We are asked to find the probability of pulling out 2 green marbles in a row if the marbles are not replaced after they're pulled out.
The probability of pulling 1st green marble will be number of green marbles divided by total marbles.
![P(\text{Green})=\frac{2}{7+3}](https://tex.z-dn.net/?f=P%28%5Ctext%7BGreen%7D%29%3D%5Cfrac%7B2%7D%7B7%2B3%7D)
![P(\text{Green})=\frac{2}{10}](https://tex.z-dn.net/?f=P%28%5Ctext%7BGreen%7D%29%3D%5Cfrac%7B2%7D%7B10%7D)
Since the marble is not replaced, so number of total green marbles will be 1 and total marbles will be 9.
Probability of getting green marble for another time will be
.
To find probability of getting 2 green marbles in a row would be product of both probabilities as:
![\text{Probability of getting 2 marbles in a row}=\frac{2}{10}\times \frac{1}{9}](https://tex.z-dn.net/?f=%5Ctext%7BProbability%20of%20getting%202%20marbles%20in%20a%20row%7D%3D%5Cfrac%7B2%7D%7B10%7D%5Ctimes%20%5Cfrac%7B1%7D%7B9%7D)
![\text{Probability of getting 2 marbles in a row}=\frac{1}{5}\times \frac{1}{9}](https://tex.z-dn.net/?f=%5Ctext%7BProbability%20of%20getting%202%20marbles%20in%20a%20row%7D%3D%5Cfrac%7B1%7D%7B5%7D%5Ctimes%20%5Cfrac%7B1%7D%7B9%7D)
![\text{Probability of getting 2 marbles in a row}=\frac{1}{45}](https://tex.z-dn.net/?f=%5Ctext%7BProbability%20of%20getting%202%20marbles%20in%20a%20row%7D%3D%5Cfrac%7B1%7D%7B45%7D)
Therefore, our required probability would be
.
Answer:
400 800 1200 1600 2000 is anwser
Answer:
im sorry i cant really see that...
Step-by-step explanation:
36/100 since there's two placement digits, we would then find the GCF (Greatest Common Factor) in this case it's 4, leaving us with 9/25 as our answer.