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3 years ago

Suppose f(x) = x². Find the graph of f(x+3). ???

Mathematics

1 answer:

alexdok [17]3 years ago

4 0

Answer: x^2+3

Step-by-step explanation:

If regular f(x) is equal to x^2, then if you just add 3 to the original, you add 3 to the same x^2. The three becomes a shift upwards on the graph. You put your vertex point up 3 on the vertical line then make your parabola

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PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER!!

musickatia [10]

Answer:

$p>\frac{1}{14}$

Step-by-step explanation:

Question: $-31p+79>-59p+81$

1) Subtract 79 from both sides:

$-31p>-59p+2$

2) Add 59p to both sides:

$28p>2$

3) Divide both sides by 28:

$p>\frac{2}{28}$

4) Simplify fraction:

$p>\frac{1}{14}$

5 0

2 years ago

2/5+x=1 What equals x?

kolbaska11 [484]

Answer:

Step-by-step explanation:

2/5 + x = 1

Multiply each term by 5

2 + 5x = 5

5x = 5 - 2

5x = 3

x = 3/5

8 0

3 years ago

Read 2 more answers

en una fiesta hay 16 personas de las cuales el 25% son mujeres, luego llegan mas mujeres a la fiesta, de tal manera que ahora lo

coldgirl [10]

Answer:

English (Ingles):
10 Women come to the party.

Spanish (Espanol):

10 Las mujeres vienen a la fiesta.

Step-by-step explanation:

English (Ingles):

We know that there are 16 people there at the start. 25% of those people are women. We can work out by subtracting 100 by 25 that 75% of the p-eople there are men. We need to do 25% of 16 so we can work out how many men and women there are there.

So we find 10% of 16 which is 1.6 then we take off 5% of 1.6 which is 0.08. We then double 1.6 to get 20% which gives us 3.2. We now add on the 5% to make it 25% which gives us 4.

This means 25% of 16 is 4.

This tells us that there are 4 women at the party and 12 men as 16 - 4 = 12.

It now says that more women arrive which makes the percentage for men go down to 60%. We now need to add 5% on to the 25% of women there are which will tell us how many more women there are now and it will let us work out how many women and men there are in total now.

As we can't do this without it giving us 4.8, we know that 25% of people is 4 women which means 50% of people would be 8 women and we make an estimate of how many women have joined which gives us 6 people which means the total amount of women at the party is 10.

Spanish (Espanol):

Sabemos que hay 16 personas allí al principio. El 25% de esas personas son mujeres. Podemos calcular restando 100 por 25 que el 75% de las personas son hombres. Necesitamos hacer el 25% de 16 para poder calcular cuántos hombres y mujeres hay allí.

Así que encontramos el 10 % de 16, que es 1,6, luego quitamos el 5 % de 1,6, que es 0,08. Luego duplicamos 1,6 para obtener el 20%, lo que nos da 3,2. Ahora sumamos el 5% para convertirlo en 25%, lo que nos da 4.

Esto significa que el 25% de 16 es 4.

Esto nos dice que hay 4 mujeres en la fiesta y 12 hombres como 16 - 4 = 12.

Ahora dice que llegan más mujeres lo que hace que el porcentaje de hombres baje al 60%. Ahora necesitamos agregar un 5% al 25% de mujeres que hay, lo que nos dirá cuántas mujeres más hay ahora y nos permitirá calcular cuántas mujeres y hombres hay en total ahora.

Como no podemos hacer esto sin que nos dé 4.8, sabemos que el 25% de las personas son 4 mujeres, lo que significa que el 50% de las personas serían 8 mujeres y hacemos una estimación de cuántas mujeres se han unido, lo que nos da 6 personas que significa que la cantidad total de mujeres en la fiesta es 10.

4 0

1 year ago

Find [5(cos 330 degrees + I sin 330 degrees)]^3

earnstyle [38]

Given a complex number in the form:
$z= \rho [\cos \theta + i \sin \theta]$
The nth-power of this number, $z^n$ , can be calculated as follows:

- the modulus of $z^n$ is equal to the nth-power of the modulus of z, while the angle of $z^n$ is equal to n multiplied the angle of z, so:
$z^n = \rho^n [\cos n\theta + i \sin n\theta ]$
In our case, n=3, so $z^3$ is equal to
$z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]$ (1)
And since
$3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}$
and both sine and cosine are periodic in $2 \pi$ , (1) becomes
$z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]$

6 0

3 years ago

Add me on sc tommyplanksnaps

DedPeter [7]

Answer:

ok lol

Step-by-step explanation:

6 0

2 years ago