All categories

3 years ago

Suppose f(x) = x². Find the graph of f(x+3). ???

Mathematics

1 answer:

alexdok [17]3 years ago

4 0

Answer: x^2+3

Step-by-step explanation:

If regular f(x) is equal to x^2, then if you just add 3 to the original, you add 3 to the same x^2. The three becomes a shift upwards on the graph. You put your vertex point up 3 on the vertical line then make your parabola

You might be interested in

Fill in the missing terms of the arithmetic sequence, -7. 1,5-13

LenKa [72]

Answer:

-3, 9

Step-by-step explanation:

The constant is 4.

7 0

3 years ago

Make c the subject: x=-b+(b²-4ac) divided by 2a The brackets mean square root

kipiarov [429]

$x=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\
2ax=-b+\sqrt{b^2-4ac}\\
\sqrt{b^2-4ac}=2ax+b\\
b^2-4ac=(2ax+b)^2\\
-4ac=4a^2x^2+4abx+b^2-b^2\\
-4ac=4a^2x^2+4abx\\
c=-ax^2-bx$

7 0

3 years ago

Use the following expression to answer the questions: g(to the second power) -4g+6. How many terms are in this expression? What

zmey [24]

G^2-4g+6
# Terms: 3, (g^2), (-4g), (6)
Variable: g
Constant: 6

4 0

3 years ago

PLEASE ANSWER QUICKLY

slavikrds [6]

Answer:

Hi ! Answers given in the pictures below

Step-by-step explanation:

7 0

3 years ago

I need help ASAP! It's urgent.. PLISSSSS

natali 33 [55]

Answer:

a) 6 mins

b) 70km/h

c) t= 45

Step-by-step explanation:

a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km

Duration

= 16 -10

= 6 minutes

b) Average speed

= total distance ÷ total time

Total time

= 24min

= (24÷60) hr

= 0.4 h

Average speed

= 28 ÷0.4

= 70 km/h

c) Average speed= total distance/ total time

Average speed

= 80km/h

= (80÷60) km/min

= 1⅓ km/min

1⅓= 28 ÷(t -24)

since duration for return journey is from t=24 mins to t mins.

$\frac{4}{3}$ (t -24)= 28

$\frac{4}{3}$ t - 32= 28

$\frac{4}{3}$ t= 32 +28

$\frac{4}{3}$ t= 60

t= $6 0\div \frac{4}{3}$

t= 45

*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.

Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)

5 0

4 years ago