Answer:
1 or 5
Step-by-step explanation:
Given the function h(x)=(2x−2)(x−5)
The zeros of h(x) are the values of x for which h(x)=0
h(x)=(2x−2)(x−5)=0
Note that if a.b=0, either a=0 or b=0.
Appying the above,
If (2x−2)(x−5)=0
Then:
2x−2=0 or x-5=0
2x=2 or x=5
x=1 0r 5
The zeroes of h(x) as defined are 1 or 5.
For the first problem the answer is -5/2
2x−7+10=−2
Step 1: Simplify both sides of the equation.
2x−7+10=−2
2x+−7+10=−2
(2x)+(−7+10)=−2
(Combine Like Terms)
2x+3=−2
Step 2: Subtract 3 from both sides.
2x+3−3=−2−3
2x=−5
Step 3: Divide both sides by 2.
2x/2=−5/2
x=−5/2
Answer:
x= -5/2
Answer:I don’t know if I’m right but imma have to say G
Step-by-step explanation:
I’m not good at math
In the absence of ATC restriction on climb or descent, and aircraft are within 1,000 feet of assigned altitude. pilots should attempt to both climb and descend at a rate of between 500 fpm and 15000 fpm. (Option A)
An Air Traffic Controller (ATC) clearance refers to an authorization by ATC for the purpose of preventing known aircraft collision. The rate of climb or descend expected by ATV is when an aircraft is within 1000 feet of assigned altitude, descend, or climb at an optimum rate consistent with the operating characteristics of the aircraft to 1,000 feet above or below the assigned altitude, and then attempt to descend or climb at a rate of between 500 and 1,500 fpm until the assigned altitude is reached.
Learn more about Air Traffic Controller (ATC):
brainly.com/question/5018782
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