Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
A) Check the first two: 2(x+5) and 2(x) + 2(5)
B) Check the last one: 14y + 2
Answer:
18 ft
Step-by-step explanation:
Since the triangle is right angled ; we could use trigonometry ;
Using the angle , 40° ; adjacent side, = 14 feets ; hypotenus = x
Cos θ = Adjacent / hypotenus
Cos 40 = 14 / x
0.7660444 = 14 / x
0.7660444x = 14
x = 14 / 0.7660444
x = 18.27
= 18 ( nearest foot)
