For this case we must solve the following quadratic equation:

With
we have:

The roots will be given by:

Where:

Substituting:

Thus, we have two roots:

Answer:

Answer:
Where is the question?
Step-by-step explanation:
Answer:
the third option
Step-by-step explanation:
108/9 = 12
Answer:
first box 9.6 2nd box 7.2 third box 12
Step-by-step explanation:
9.6 is the missing height 12 is the hypotenuse is always last
Answer: a and b
Step-by-step explanation: