ANSWER
The correct answer is 
.
<u>EXPLANATION</u>
We were given the matrix equation;
![\left[\begin{array}{cc}n-1&6\\-19&m+3\end{array}\right] +\left[\begin{array}{cc}-1&0\\16&-8\end{array}\right] =\left[\begin{array}{cc}10&6\\-3&40\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dn-1%266%5C%5C-19%26m%2B3%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%260%5C%5C16%26-8%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D10%266%5C%5C-3%2640%5Cend%7Barray%7D%5Cright%5D)
.
We must first simplify the Left Hand Side of the equation by adding corresponding entries.
![\left[\begin{array}{cc}n-1+-1&6+0\\-19+16&m+3-8\end{array}\right]=\left[\begin{array}{cc}10&6\\-3&40\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dn-1%2B-1%266%2B0%5C%5C-19%2B16%26m%2B3-8%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D10%266%5C%5C-3%2640%5Cend%7Barray%7D%5Cright%5D)
.
That is;
![\left[\begin{array}{cc}n-2&6\\-3&m-5\end{array}\right]=\left[\begin{array}{cc}10&6\\-3&40\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dn-2%266%5C%5C-3%26m-5%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D10%266%5C%5C-3%2640%5Cend%7Barray%7D%5Cright%5D)
.
Since the two matrices are equal, their corresponding entries are also equal. we equate corresponding entries and solve for m and n.
This implies that;
We got this equation from row one-column one entry of both matrices.
Also, the row three-column three entries of both matrices will give us the equation;
Hence the correct answer is .
The correct option is option 2
Answer: 7x+y=-6
Step-by-step explanation: Hope <em> I helped</em>
To add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array} gives <u>A) 399</u>.
<h3>What is an array?</h3>
An array is a data structure made up of some elements.
The sum of all elements in an array is found by adding up the elements in the array.
<h3>Data and Calculations:</h3>
Elements of the array = 37, 202, and 160
The sum of the array, 37 + 202 + 160 = 399
Thus, to add or sum this arrary, beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array} gives <u>A) 399</u>.
Learn more about arrays at brainly.com/question/23698059
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<h3>Question:</h3>
Add beg ∈ {array} {r} 37 \202\ + 160/ ∈ end {array}
<h3>Answer Options:</h3>
A) 399
B) 389
C) 400
D) 409
Answer:
I think it would be a <em>#Number</em>
Step-by-step explanation:
