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Murrr4er [49]
3 years ago
10

The 6th term of (x^3− 1) ^8

Mathematics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

=x24−8x21+28x18−56x15+70x12−56x9+28x6−8x3+1

Step-by-step explanation:

=(x3−1)8

=(x3−1)*(x3−1)*(x3−1)*(x3−1)*(x3−1)*(x3−1)*(x3−1)*(x3−1)

=x24−8x21+28x18−56x15+70x12−56x9+28x6−8x3+1

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For function of g,g(0)=1 and g(1)=5 assuming g is a linear function what is g(3)<br>​
lawyer [7]

Answer:

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Step-by-step explanation:

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Required

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