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2 years ago

2 cups is to 8 cans as 14 cups is to ___ cans?

Mathematics

2 answers:

STALIN [3.7K]2 years ago

7 0

Answer:

Step-by-step explanation:

The ratio is 1:4

14 * 4 = 56

devlian [24]2 years ago

7 0

Answer: 56

Step-by-step explanation:

8 ÷ 2 = 4 (cans) - it is 1 cup.

14 × 4 = 56 (cans) - it is 14 cups.

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PLZ HELP ILL MARK BRANLEIST

DaniilM [7]

Answer:

I'm pretty positive it's (-4,-2)

Step-by-step explanation:

i looked at the grid

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1 year ago

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The <em>integrating factor </em>is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

3 years ago

Which one is equivalent to the problem ? please help me!!!

lesya692 [45]

Answer:

Step-by-step explanation:

This is a power to a power problem. -3 times 2 equals-6. Usually when a number is raised to a negative power, the number is the denominator over 1...with the exponent in the denominator ad well. 5 to the -6 power is 15,605 which is the same as 1/5 to the 6th power....1/15,605

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3 years ago

I might not respond for a little while, please don’t end the session! Need help on #3 and 4

slavikrds [6]

We have a right triangle with a 15m hypotenuse and a 8m leg. If we use x for the missing leg then the Pythagorean Theorem states that:

$15^2=8^2+x^2$

Then we have to solve that equation for x:

$\begin{gathered} x^2=15^2-8^2=225-64 \\ x^2=161 \\ x=\sqrt[]{161} \end{gathered}$

So the answer is the square root of 161.

3 0

1 year ago

What is the common ratio between successive terms in the sequence 1.5, 1.2, 0.96, 0.768

Pani-rosa [81]

Answer:

To determine the common ratio of a geometric sequence. You just need to divide any two consecutive terms on it. You can see below that all of them have the same quotient.

1.2 / 1.5 = 0.8

0.96 / 1.2 = 0.8

0.768 / 0.96 = 0.8

Decimal form = 0.8

Fraction form = 4/5

Check:

1.5 x 0.8 = 1.2

1.5 x 4/5 = 6/5 = 1 1/5 = 1.2

Therefore, the common ratio between successive terms in the sequence? 1.5, 1.2, 0.96, 0.768 is 0.8 or 4/5.

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3 years ago