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MrMuchimi
3 years ago
8

Why are 7 and 2 like terms? help please!!

Mathematics
1 answer:
bazaltina [42]3 years ago
7 0

Like terms are terms whose variables are the same. In this case, 7 and 2 have no coefficients therefore are like terms. For example, 7x and 2x would both be like terms because they have the same coefficient which is x.

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A restaurant will select select 1 card from a bowl to win a free lunch. Jimmy put in 10 cards in the bowl. The bowl has a total
amid [387]
If he put 10 in the bowl and there are 150 cards, the chance for him to win would be 10/150.
now by simplifying it, you get 1/15.
therefore answer is C
5 0
3 years ago
Rewrite with only sin x and cos x.
Annette [7]

Option A

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

<em><u>Solution:</u></em>

Given that we have to rewrite with only sin x and cos x

Given is cos 3x

cos 3x = cos(x + 2x)

We know that,

\cos (a+b)=\cos a \cos b-\sin a \sin b

Therefore,

\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x  ---- eqn 1

We know that,

\sin 2 x=2 \sin x \cos x

\cos 2 x=\cos ^{2} x-\sin ^{2} x

Substituting these values in eqn 1

\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)  -------- eqn 2

We know that,

\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x

Applying this in above eqn 2, we get

\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)

\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}

\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x

Therefore,

\cos 3 x=\cos x-4 \cos x \sin ^{2} x

Option A is correct

7 0
3 years ago
In the figure, AA′ = 33 m and BC = 7.5 m. The span is divided into six equal parts at E, G, C, I, and K. Find the length of A′B.
Umnica [9.8K]
The correct answer for the question that is being presented above is this one: "18.12."
The image of this triangle is an isosceles triangle<span> with the base being 33 m (from angle A to angle A') and the right leg is 7.5 m long (BC) the span or width of the triangle is divided by 6 vertical lines with equal distances from each other. so we need to find the length of the left leg AB.</span>
4 0
3 years ago
Which of the following is not equivalent
dsp73
90/139 is the only fraction not equivalent to 45/70.

To find if a fractions are equivalent, divide the numerator by the denominator for each fraction.

45/70=0.642857
27/42=0.642857
9/14=0.642857
63/98=0.642857

Notice how all of these get you the same number. However, when you divide 90 by 137, you get 0.64748, which is not the same as the others. Therefore, 90/137 is the fraction that is not equivalent to 45/70.

6 0
3 years ago
Read 2 more answers
The following data points are the yearly salaries (in thousands of dollars) of the 4 high school cheerleading
GarryVolchara [31]

Answer:

6

Step-by-step explanation:

5 0
3 years ago
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