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tia_tia [17]
3 years ago
8

It takes 3 1/2 gallons of gas to travel 8 and 3/4 miles what is the unit rate of miles per gallon

Mathematics
1 answer:
valentinak56 [21]3 years ago
8 0

Answer:

2 1/2 miles per gallon

Step-by-step explanation:

So to travel 8 3/4 miles, we need 3 1/2 gallons of gas. All we need to do is divide the gallons of gas by miles. So we would do 8 3/4 divided by 3 1/2. 3 1/2 goes into 8 3/4 2 1/2 times.

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A girl has 98 beads, and all but 14 were lost. how many beads did she loose?<br>​
castortr0y [4]

Answer:

84 beads

Step-by-step explanation:

She had 98 beads and lost all but fourteen. So it would be 98 - 14 which would get you 84 beads that the girl has lost

8 0
3 years ago
Rewrite the expression by combining like terms.<br> 3xy + 8x^2+ 4y + 2y - 5x^2
Lelu [443]

Answer:

3x^2 + 3xy + 6y

Step-by-step explanation:

7 0
3 years ago
Box 1 measures 6cm in width, 12cm in length, and 4cm in height. The height is doubled to 8cm to produce a larger box, Box 2 Whic
arlik [135]

Step-by-step explanation:

i don't know but i think this is it

The height is doubled to 8cm to produce a larger box, Box 2 Which phrase accurately describes the volume of Box 2

6 0
3 years ago
A bag of oranges weighs 5 1/4 pounds. How much does 1 1/2 bags weigh?
Andreyy89

Answer:

you simplify the fractions then you cross multiply

Step-by-step explanation:

1/2 * 4/2 you multiply 1 and 4 and you get 4/4 which is equal to 1  

3 0
4 years ago
Hard math question!
luda_lava [24]
First, let me show you some notation.

To show a matrix is an inverse of another matrix, we write A^{-1}

-1 is not an exponent. It just shows that a matrix is an inverse of another matrix.

For a 2x2 matrix, we can get the inverse by first making b and c negatives and swap the positions of a and d.

Then multiply each entry in the matrix by 1 divided by the determinant.

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]^{-1} = &#10;  \frac{1}{ad - bc}\left[\begin{array}{ccc}d&{-b}\\{-c}&a\end{array}\right] =  \\  \\ \\ \left[\begin{array}{ccc}d(\frac{1}{ad-bc})&{-b}(\frac{1}{ad-bc}) \\ {-c}(\frac{1}{ad-bc}) &a(\frac{1}{ad-bc}) \end{array}\right]

I hope this helped!
8 0
3 years ago
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