Monthly interest, i = APR/12 = 0.06/12 = 0.005
Monthly payment, A = $450
Period, n = 36 (months)
Future value of payment
= A((1+i)^n-1)/i
= 450((1.005^36-1)/0.005
= 17701.2472341
Future value of car
F = future value of payment + residual value
= 17701.2472341 + 20000
= 37701.2472341
Present value of car
= downpayment + present value of future payments
= 1500 + F/(1+i)^36
= 1500 + 37701.2472341/(1.005^36)
= 1500 + 31504.86
= 33004.86
If u add 125 times 8 it will equal 1000
becouse
then
you also can combine it (if this is what are you looking for..)
or any other combination like:
or:
Answer: B -4
Step-by-step explanation: I think it is B because -4 is smaller than A,C and D.
We can set up this equation using this formula:
a = p(1 + r/n)^nt
p = starting amount.
r = interest.
n = number of times it's compounded in a year
t = years
We'd set it up like this:
a = 50(1 + ?/1)^1(12)
Because we're missing the amount of interest, it would be impossible to tell what the amount would be after 12 years.
