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Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

i think the answer is 10-11 but i'm not sure i'm sorry

Step-by-step explanation:

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ALGEBRA 2!!!!!!!!! SHOW YOUR WORK!!!!!!!!!!!!!<br> Do f(g(x)) and g(f(x))

bezimeni [28]

$\bf f(x)=\cfrac{2x-3}{x+1}~\hspace{10em}g(x)=\cfrac{x+3}{2-x}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
f(~~g(x)~~)\implies \cfrac{2[g(x)]-3}{[g(x)]+1}\implies \cfrac{2\left( \frac{x+3}{2-x} \right)-3}{\left( \frac{x+3}{2-x} \right)+1}\implies
\cfrac{\frac{2x+6}{2-x}-3}{\frac{x+3}{2-x}+1}
\\\\\\
\cfrac{\frac{2x+6-6+3x}{2-x}}{\frac{x+3+2-x}{2-x}}\implies \cfrac{2x+6-6+3x}{2-x}\cdot \cfrac{2-x}{x+3+2-x}\implies \cfrac{5x}{5}\implies x$

$\bf \rule{34em}{0.25pt}\\\\
g(~~f(x)~~)\implies \cfrac{[f(x)]+3}{2-[f(x)]}\implies \cfrac{\frac{2x-3}{x+1}+3}{2-\frac{2x-3}{x+1}}\implies \cfrac{\frac{2x-3+3x+3}{x+1}}{\frac{2x+2-(2x-3)}{x+1}}
\\\\\\
\cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-(2x-3)}\implies \cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-2x+3}
\\\\\\
\cfrac{5x}{5}\implies x$

and in case you recall your inverses, when f( g(x) ) = x, or g( f(x) ) = x, simply means, they're inverse of each other.

4 0

3 years ago

How to graph 14x+18y=126

Burka [1]

We need to rearrange this into $y=my+c$
Subtract 14x from both sides
$18y=-14x+126$
Divide both sides by 2
$9y=-7x+63$
Divide both sides by 9
$y=\frac{-7x+63}{9}=\frac{-7x}{9} +\frac{63}{9}$
Plot the point (0, 63/9)
Then pick some x values and put them into the equation to find the respective y values
Then plot those points
Finally join up those points