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Gelneren [198K]
2 years ago
15

What does the 50th term of this arithmetic sequence: 29,32,35,38

Mathematics
1 answer:
frozen [14]2 years ago
3 0

Answer:

176

Step-by-step explanation:

First term (a) = 29

Common difference (d) = 32 - 29 = 3

For calculating the 50th term , n = 50

Now

t_{50} = a + ( n - 1) d\\t_{50} = 29 + ( 50 - 1 ) *3\\ t_{50} = 29 + 147\\t_{50} = 176

hope it will help :)

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See below for the terms, coefficients, and constants in the variable expressions

<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>

To determine the terms, coefficients, and constants, we use the following instance:

ax + by + c

Where the variables are x and y

  • Then the terms are ax, by and c
  • The coefficients are a and b
  • The constant is c

Using the above as guide, we have:

A) 2b + 2ac+5

  • Terms: 2b, 2ac, 5
  • Coefficient: 2, 2 and 5
  • Constant 5

B) 34abx + 16y +1

  • Terms: 34abx, 16y, 1
  • Coefficient: 34ab, 16
  • Constant: 1

C) st +4u + v

  • Terms: st, 4u, v
  • Coefficient: 4

D) 14xy + 6

  • Terms: 14xy, 6
  • Coefficient: 14, 6
  • Constant 6

E) 14x + 12y

  • Terms: 14x, 12y
  • Coefficient: 14, 12

F) 3+ 6-7+a

  • Terms: 3, 6, -7, a
  • Coefficient: 1
  • Constant: 3, 6, -7

Read more about terms, coefficients, and constants at:

brainly.com/question/14625487

#SPJ1

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