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Nadusha1986 [10]
3 years ago
5

Please solve and explain how you got the answer

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0
500 X 6 = 3000, then 6 X 1.6 = 9.6, so the answer is A, -9.6
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The point (2, 4) is on the graph of f(x) = x2. What is the value of b if the point (0.5, 4) is on the graph of f(bx)?
zloy xaker [14]

Answer:

8

Step-by-step explanation:

b(0.5) = 4

b = 4/0.5

b = 8

7 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,
tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let \bar X = <u><em>sample mean diameter</em></u>

The z score probability distribution for sample mean is given by;

                            Z  =  \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} }  } }  ~ N(0,1)

where, \mu = population mean diameter = 141 millimetres

           \sigma = standard deviation = 7 millimetres

           n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P(\bar X > 141.4 millimetres)

      P(\bar X > 141.4) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} }  } } > \frac{141.4-141}{\frac{7}{\sqrt{39} }  } } ) = P(Z > 0.36) = 1 - P(Z \leq 0.36)

                                                            = 1 - 0.6406 = <u>0.3594</u>

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

8 0
4 years ago
Construct the indicated confidence interval for the population mean using the​ t-distribution. Assume the population is normally
DanielleElmas [232]

Using the t-distribution, it is found that the confidence interval is (14.2, 14.8).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a <em>two-tailed 95% confidence interval</em>, with 18 - 1 = <em>17 df</em>, is t = 2.1098.

The other parameters are given by:

\overline{x} = 14.5, s = 0.68, n = 18.

Hence, the bounds of the interval are given by:

\overline{x} - t\frac{s}{\sqrt{n}} = 14.5 - 2.1098\frac{0.68}{\sqrt{18}} = 14.2

\overline{x} + t\frac{s}{\sqrt{n}} = 14.5 + 2.1098\frac{0.68}{\sqrt{18}} = 14.8

The confidence interval is (14.2, 14.8).

More can be learned about the t-distribution at brainly.com/question/16162795

4 0
3 years ago
What is the x-intercept of the following function?<br> h(x) = 4x+3 - 2
ddd [48]

Answer:

Let h(x) = y

y = 4^(x+3) -2

For x intercept let y = 0

2 = 4^(x+3)

2= 2^2(x+3)

1 = 2x +6

2x = -5

2x = -5

Divide by 2

x = -5/2

The x intercept for the function is ( -5/2, 0)

Hope this helps.

4 0
3 years ago
Read 2 more answers
Solve for y 3y+12=-6
Vadim26 [7]

Answer:

y=-6

Make sure to tell me if im right

Step-by-step explanation:

3 0
3 years ago
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