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sergiy2304 [10]
3 years ago
5

DUE IN 2 MINUTES HELP

Mathematics
2 answers:
o-na [289]3 years ago
6 0

I think it’s D or A

Step-by-step explanation: D or A

mrs_skeptik [129]3 years ago
3 0

Answer: B is the answer

Step-by-step explanation:

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The function f(x) varies inversely with x and f(x)=2 when x = 16.<br><br> What is f(x) when x = 4?
andrew-mc [135]

Answer: The correct answer is:  [D]:  "8" .

Step-by-step explanation:f y varies inversely with x;  then y = k/x ; with "k" being the "constant" in this equation.  

You can find the constant by substituting the values given: x = 16,  f(x) = y = 2 ;

So, f(x) = y = 2  = k/16 ;

→  2 = k / 16 ;

Solve for the constant; "k" ;

Multiply EACH SIDE of the equation by "16"

→  16* (2) = (k / 16) * 16 ;

→  32 = k ;

 ↔  k = 32 ;  

As such, we can write the equation:

y = k/ x ; as:

→  y = 32/ x ;

Since we are given:  "x = 4" ;  Plug in that value; and solve for "y" ;

y = 32/4 = 8 .

y = 8 .

y = f(x) ;

So;  f(x) = 8 ;  which is:  Answer choice:  [D]:  "8" .

8 0
3 years ago
Kiera takes piano lessons and currently knows 6 pieces. She learns two new pieces each week.
Marrrta [24]

Answer:

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對他在售價將其所台

Step-by-step explanation:

女4自?日

3 0
3 years ago
Find the value of the expression -6 + -3 ​
mamaluj [8]

Answer:

-9

Step-by-step explanation:

Adding a negative 3 is the same as subtracting 3, so if you do -6 - 3 you get -9

4 0
3 years ago
21 is 60% of what number
irga5000 [103]
The answer is 12.6 %.
60% = 60 / 100 = 0.6

 60% of 21
= 60% * 21
= 0.6 * 21
= 12.6
6 0
4 years ago
Read 2 more answers
Factor the GCF: 12a^3b + 8a^2b^2 — 20 ab^3
geniusboy [140]

Answer:

GCF is 4ab

And the expression will be: 4ab ( 3a^2+2ab-5b^2)

Step-by-step explanation:

Factor the GCF :

12a^3b + 8a^2b^2-20 ab^3

We need to find the common terms that are common in each of the term given above

12,8 and 2 are all divisible by 4

a is common in all terms and b is also common in all terms,

So, GCF is 4ab

Taking 4ab common

12a^3b + 8a^2b^2-20 ab^3=4ab ( 3a^2+2ab-5b^2)

5 0
4 years ago
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