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4 years ago

(tan0 + 1)(csc? 0) = tan? 0 + cot? 0 + 2

Mathematics

1 answer:

AnnyKZ [126]4 years ago

6 0

Answer:

Step-by-step explanation:

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Margot planted a rectangular garden that was 18 feet long and 10 feet wide. How many feet of fencing will she need to go all the

slamgirl [31]

Find the perimeter when it says fencing 2(width + length)

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4 years ago

Solve each equation by factoring ! NEED THIS IN 5 MIN ILL GIVE YOU BRAINLIEST!

sertanlavr [38]

for problem 6, you will want to subtract both sides by 5.

n^2 + 7n + 10 = 0

then factor:

(n + 5) (n + 2) = 0

n+ 5 = 0, n +2 = 0

n = -5, n = -2

----------------------------

for problem 7, add - 12 and - 6 together

n^2 + 3n - 18

<em>(you can put </em>= 0 <em>next to the equation since that can make it easier to solve, I guess)</em>

n^2 + 3n - 18 = 0

then factor:

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n = -6, n = 3

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3 years ago

Fill in the other coordinate for the line y= 2/3x+3:(3,?)

DiKsa [7]

Y = 2/3x + 3

If x = 3, plug it in the equation to find y for (3 , y)

y = 2/3(3) + 3
y = 6/3 + 3
y = 2 + 3
y = 5

(3 , 5)

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3 years ago

What mixed number is equavilant to 3/4 as a mixed number

olga2289 [7]

Answer: do the reciprocal

Step-by-step explanation: flip it

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3 years ago

A college student organization wants to start a nightclub for students under the age of 21. To assess support for this proposal,

eduard

Answer:

a) Sample size = 822

b) Margin of error = 0.03407

Step-by-step explanation:

We are given the following in the question:

p = 74% = 0.74

a) Sample size is required to obtain margin of error of 0.03

Formula:

$\text{Margin of error} = z_{\text{statistic}}\times \sqrt{\dfrac{p(1-p)}{n}}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get,

$0.03 = 1.96\times \sqrt{\dfrac{0.74(1-0.74)}{n}}\\\\n = (\dfrac{1.96}{0.03})^2(0.74)(1-0.74)\\\\n = 821.24 \approx 822$

Thus, the sample size must be approximately 822 to obtain a 95% confidence interval with an approximate margin of error of 0.03

b) Margin of error for the 95% confidence interval

p = 54% = 0.54

Formula:

$\text{Margin of error} = z_{\text{statistic}}\times \sqrt{\dfrac{p(1-p)}{n}}}$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get,

$\text{Margin of error} = 1.96\times \sqrt{\dfrac{0.54(1-0.54)}{822}}\\\\=0.03407$

The margin of error now will be 0.03407.

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4 years ago