Answer: 1/90
multiply 1/10 and 1/9 across, and you get 1/90
×
= 
hope it helps!!!
Answer:
Between 15.95 ounces and 16.15 ounces.
Step-by-step explanation:
We have the following value m, being the mean, sd, being the standard deviation and n, the sample size:
m = 16.05
sd = 0.1005
n = 4
We apply the formula of this case, which would be:
m + - 2 * sd / (n ^ 1/2)
In this way we create a range, replacing we have:
16.05 + 2 * 0.1005 / (4 ^ 1/2) = 16.1505
16.05 - 2 * 0.1005 / (4 ^ 1/2) = 15.9495
Which means that 95% of all samples are between 15.95 ounces and 16.15 ounces.
Answer:
2 pages per minute
Step-by-step explanation:
when you divide 7 by 3, your answer would be 2.3333333333 and so on.
however, you can say
iT pRiNtS 2 aNd A tHiRd pAgEs PeR MiNuTe.
you should say it prints 2 whole pages a minute.
i hope this helps!
stay safe!
:)
9.81 or 98.1 pretty sure it's the first one
Answer:
sample size n would be 149305 large
Value of n (149305) is too high, this will be the practical problem with attempting to find this confidence interval
Step-by-step explanation:
Given that;
standard deviation α = 150 min
confidence interval = 99%
since; p( -2.576 < z < 2.576) = 0.99
so z-value for 99% CI is 2.576
E = 1 minutes
Therefore
n = [(z × α) / E ]²
so we substitute
n = [(2.576 × 150) / 1 ]²
n = [ 386.4 ]²
n = 149304.96 ≈ 149305
Therefore sample size would be 149305 large
Value of n is too high, that would be the practical problem with attempting to find this confidence interval