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Allisa [31]
3 years ago
8

What are the excluded values of x for x^2-9x/x^2-7x-18

Mathematics
2 answers:
Crazy boy [7]3 years ago
8 0
The expression is \displaystyle{\frac{x^2-9x}{x^2-7x-18}.

The excluded values are those values of x for which the denominator, x^2-7x-18, becomes zero.

So, we need to factorize the expression x^2-7x-18.


To factorize the expression, we can use the grouping method. Write -7x as -9x+2x to create 4 terms, as follows:

                          x^2-7x-18=(x^2-9x)+(2x-18)=x(x-9)+2(x-9).

The, factorizing (x-9), we have (x-9)(x+2).

This expression becomes 0 for x=-2, or for x=9.


Answer: {-2, 9}
erma4kov [3.2K]3 years ago
8 0

Answer:

option c

Step-by-step explanation:

im taking the test Ω

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