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Jobisdone [24]
3 years ago
13

Find the Unit Rate: juan walks 6 miles in 3 hours.

Mathematics
1 answer:
timama [110]3 years ago
6 0

Answer: Juan walks 3 miles in 1 hour.

Step-by-step explanation:

3 mi/ 1 hr is the unit rate because you are supposed to turn it into a fraction and simplify it.

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If the length of AC equals 30, what is the length of the midsegment DE? A) 10 B) 15 C) 20 D) 25
Serhud [2]

Answer:

Step-by-step explanation:

10

3 0
3 years ago
The speed of a boat in still water is 40 mph. If it takes the same time for the boat to travel 8 miles upstream as it does to tr
antoniya [11.8K]

Answer:

Current speed is 40mph

Step-by-step explanation:

We firstly need to know what is intended by upstream and downstream. When the boat travels in the direction of the current (horizontal movement of the water), we say it is moving downstream otherwise it is moving upstream.

Let's assume the speed of the boat is A and that of the current is B, then the speed when it moves dowstream would be A + B and the speed if it moves upstream would be A – B.

In this question, we know that the speed of the boat is 40mph. Given that it takes the same time to travel 8miles upstream as it does to travel 24miles downstream, we have

Speed upstream = 8/t

Speed downstream = 24/t

Respectively.

Let speed of current be X, then

Speed downstream = 40 + X

Speed upstream = 40 – X

From the question we have:

(40 + x)/24 = (40 – X)/8

(40 + x)/3 = (40 – x)/1

3(40 – x) = 40 + X

120 – 3x = 40 – X

120 – 40 = 3x – X

2x = 80

X = 40.

Therefore, current speed is 40mph

5 0
2 years ago
What is the equation of the lime that passes through the point (1,3) and has a slope of 6
Ilya [14]

Answer:

y = 6x+ 3.

Step-by-step explanation:

y - y1 = m(x - x1)

sub.

distribute.

bring down and solve.

7 0
3 years ago
Read 2 more answers
What is the value of x? Help me please
Basile [38]
168 degrees
180-12=168
5 0
3 years ago
Simplify sin q + cosq cotq.
IRINA_888 [86]
\sin q+\cos q\cot q=\sin q+\cos q\cdot\dfrac{\cos q}{\sin q}=\sin q+\dfrac{\cos^2q}{\sin q}\\\\=\dfrac{sin^2q}{\sin q}+\dfrac{\cos^2q}{\sin q}=\dfrac{\sin^2q+\cos^2q}{\sin q}=\dfrac{1}{\sin q}=\csc q\\\\Used:\\\cot q=\dfrac{\cos q}{\sin q}\\\\\sin^2q+\cos^2q=1\\\\\csc q=\dfrac{1}{\sin q}
3 0
3 years ago
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