If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:
(x,y)=((6+2)/2, (3+1)/2)=(4,2)
Now we need to find the radius....the diameter is:
d^2=(6-2)^2+(3-1)^2
d^2=16+4
d^2=20 since d=2r, r=d/2, and r^2=d^2/4 so
r^2=5
The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:
(h,k)=(4,2) from earlier so:
(x-4)^2+(y-2)^2=5
Answer:
The answer is C trust me I did this
Y=Mx+B -> slope intercept form
The answer would be -3y=-5x-9
Divide the -3 on both sides and you get
y=5/3x+3
Answer:
8z+5
Step-by-step explanation:
Let's split the expression into two terms- z and... not z :)
3z+5z=8z
Why? it's just 3+5 with z tacked on the end
14-9=5
simple math :)
put it together to get
8z+5
all done!
lmk if you have any more questions
