Answer:

Step-by-step explanation:
<u>Properties of Logarithms</u>
We'll recall below the basic properties of logarithms:

Logarithm of the base:

Product rule:

Division rule:

Power rule:

Change of base:

Simplifying logarithms often requires the application of one or more of the above properties.
Simplify

Factoring
.

Applying the power rule:

Since


Applying the power rule:

Applying the logarithm of the base:

3x=4+13x=5x=5/32x=2* 5/32x=10/3
Answer:
6x ≥ -24
x ≥ -4
Step-by-step explanation:
the inequality of Six times a number x is at least −24
6x ≥ -24
Divide each side by 6
6x/6 ≥ -24/6
x ≥ -4
Answer:
since there are an even number of negatives, just ignore them and multiply normally. 2 x 2=4
4 x 2=8
8 x 2=16
The answer is 16
It will increase by 5/9 of a degree.
If you convert the given equation into slope intercept form, you will have:
c = (5/9)f + 160/9
In this form, it is easier to see the slope. The line would be increase by a rate of 5/9.