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KATRIN_1 [288]
2 years ago
8

PLEAS HELP ILL GIVE BRAINLIEST PLEASE SHOW WORK

Mathematics
2 answers:
sp2606 [1]2 years ago
8 0

Answer:

the answer is

13 / 40 = 32.5%

ololo11 [35]2 years ago
7 0

Answer: its A

Step-by-step explanation:

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Laura creates a rectangular prism with wooden cubes. Each cube has an edge length of 3/4 inch. she uses a total of 240 cubes. th
kirill115 [55]

Answer:00.24

explanation:

Just add the decimal form and multiply the 240 with the decimal of the 3/4

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Kendra has a math test every 12 school days and a vocabulary test every 9 school days. She had both a math test and a vocabulary
klasskru [66]
You need the Least Common Multiple of 12 and 9.

That's 36.

3 x 12 = 36
4 x 9 = 36
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Solve the equation ƒ - (-4) = 12.<br> ƒ = -8<br> ƒ = 16<br> ƒ = 8<br> ƒ = -9
Anarel [89]

Step-by-step explanation:

-8 - -4= -8+4=-4

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19.47 is what percent of 29.5
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What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
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