Answer:
124°
Step-by-step explanation:
Not the best at explaining but should be equal to 180 straight across. You have to find the missing angle. You know the right angle is 90° so you will add 34° to get 124°. 180-124 will get you 56°. Straught across you have the angle that you are trying to find which is 124° because 180-56 is 124.
Answer:
4th option
Step-by-step explanation:
open circle means more than or less than
n is more than -3 but less than 1
Solving
we get, 
Step-by-step explanation:
We need to solve: 
Solving:

Adding -ln(2) on both sides:


Using logarithmic rule: if 
So,

Simplifying:

So, Solving
we get, 
Keywords: Logarithms
Learn more about Logarithms at:
#learnwithBrainly
Answer:because it works different when you smell a chemical sense from then if you smell a regular sese.
Step-by-step explanation:
A regula sense like a fart might smell bad. But a chemical sense can burn your nostrils and burn you nose hairs causing you not to have good sent or to never smell again
<h3>
<u>Answer:</u></h3>

<h3>
<u>Step-by-step explanation:</u></h3>
A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.
The inequality given to us is :-

Let's plot a graph to see its interval . Graph attached in attachment .
Now we can see that the Interval notation of would be ,
![\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Corange%20%5Ctt%20%5Cpurple%7B%5Cleadsto%7Dy%20%5Cin%20%5B-2%2C-1%5D%20%7D%7D)
<h3>
<u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>