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pochemuha
2 years ago
5

Interval of [0⁰,360⁰]3 sin² tan 0-3 sin²0 = 020 points​

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
6 0

Answer:

 

θ=41.3∘,138.7∘,221.3∘,318.7∘ Explanation: 3sin2θ−10(1−2sin2θ)=0 23sin2θ−10=0 s

Step-by-step explanation:

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Write the slope intercept form of each line.
Solnce55 [7]

Answer:

8

Step-by-step explanation:

7 0
2 years ago
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Find the gcf of 8x and 22xy
Ksivusya [100]
The greatest common factor of 8x and 22yx is 2x.
I got this answer by factoring out 8 and 22:

8: 1,2,4,8
22: 1,2,11,22

Their greatest common factor was 2 and they both have x.

Your answer is 2x. 

Hope this helped! :)
6 0
3 years ago
Read 2 more answers
Short Response
garik1379 [7]

Answer:

(a)2(89x+84)

(b)2(89x+84-x^2\pi)

Step-by-step explanation:

The dimensions of the larger rectangular field are:

  • Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

  • Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain =\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi

Area of the Field that does not include the soccer  field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)

8 0
3 years ago
#5 10 pounds of Cat Food A costs $6.50.
slava [35]

Answer:

A

Step-by-step explanation:

6 is less than 14 obviously.

6 0
2 years ago
Please help! Ill mark brainliest if correct! help ASAP
amm1812

Answer:

Its 1,020

Hope u get it right!!!

U got this!!!!!!!!!!

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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