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sukhopar [10]
3 years ago
8

Nervous tissue forms nerves that vary in length. The flexibility of nerve length allows communication to occur between regions o

f the body that are very close to each other, or very far away from each other. One example of a very long nerve is the sciatic nerve, which runs from the spinal cord to the toes and is approximately one meter long. Which of the following is supported by the passage?
A. Only distant regions would communicate using nervous tissue
B. Only nearby regions would communicate using nervous tissue
C.Both distant and nearby regions would communicate using nervous tissue
D. Neither distant nor nearby body regions would communicate using nervous tissue
Biology
2 answers:
xz_007 [3.2K]3 years ago
8 0
The correct answer is C. It's very obvious from the passage that the nerves may reach the distant regions like the sciatic nerve that communicates between the spinal cord and the toes. The nerve is a tissue that is composed of different types of cells. mainly, the nerve contains the nerve bundles. Each nerve bundle consists of a group of axons of nerve cells grouped together in a sheath. The nerve tissue an artery and a vein for the blood supply. The nerve may reach 2 meters long in some cases and may have branches.
MatroZZZ [7]3 years ago
7 0
<span>C.Both distant and nearby regions would communicate using nervous tissue

An impulse from nervous tissue must be transmitted to the brain to be perceived. A long nervous tissue will transmit everything in their path. The nerve is not only traveling to the toes but also branched to nearby tissue so it can capture any impulse. </span>
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(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}

10th\ run = 9

So:

B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

Required

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(a) & (d) Median Comparisons

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}                         B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

n = 9                                                         n = 10

Arrange the data:

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

                               Median = \frac{n + 1}{2}th

Median = \frac{9 + 1}{2}th                            Median = \frac{10 + 1}{2}th

Median = \frac{10}{2}th                              Median = \frac{11}{2}th

Median = 5th                                 Median = 5.5}th --- average of 5th and 6th

Median = 2                                    Median = \frac{2+2}{2} = 2

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

n = 9                                                         n = 10

First, calculate the lower quartile (Q1)

Q_1 = \frac{n + 1}{4}th[Odd n]             Q_1 = \frac{n}{4}th [Even n]

Q_1 = \frac{9 + 1}{4}th                            Q_1 = \frac{10}{4}th

Q_1 = \frac{10}{4}th                              Q_1 = 2.5

Q_1 = 2.5th                              

This means that:

Q_1 = 2nd + 0.5(3rd - 2nd)              Q_1 = 2nd + 0.5(3rd - 2nd)

Q_1 = 1 + 0.5(1- 1)                   Q_1 = 1+ 0.5(1 - 1)                      

Q_1 = 1                                       Q_1 = 1

Next, calculate the upper quartile (Q3)

Q_3 = \frac{3}{4}(n + 1)th [Odd n]             Q_3 = \frac{3}{4}(n)th [Even n]

Q_3 = \frac{3}{4}(9 + 1)th                            Q_3 = \frac{30}{4}th

Q_3 = \frac{30}{4}th                                     Q_3 = 7.5th  

Q_3 = 7.5th                                    

This means that:

Q_3 = 7th + 0.5(8th- 7th)           Q_3 = 7th + 0.5(8th- 7th)

Q_3 = 2 + 0.5(3- 2)                       Q_3 = 2+ 0.5(4 - 2)                      

Q_3 = 2.5                                       Q_3 = 3

The interquartile range is  IQR = Q_3 - Q_1

So, we have:

IQR = 2.5 - 1                  IQR = 3 - 1

IQR = 1.5                       IQR  =2

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

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