All categories

2 years ago

Please help! Thank you if you do :)

Mathematics

1 answer:

Kruka [31]2 years ago

6 0

Step-by-step explanation:

A(-5,1) and B(0,4)

$m \: = \: \frac{y2 - y1}{x2 - x1}$

X1=0 , Y1=4 X2= -5 , Y2=1

$m \: = \: \frac{3 }{5}$

$y - y1 = m(x - x1)$

y - 4 = ⅗(x-0) ==> y - 4 = ⅗ X ==> y = ⅗ X + 4

C is the answer

You might be interested in

Work out the area of the shaded region.

Makovka662 [10]

Answer: Area of the shaded region is 6.867 square cm

Step-by-step explanation:

The shaded area corresponds to the difference of the area of the rectangle and the area of the semicircle.

Area of the rectangle = 4 times 8 = 32 cm^2

Area of the semicircle = 0.5 * pi * r^2 (where r is the radius, i.e., half of the diameters, i.e., 4 cm). So Area = 0.5*pi*4^2 = 25.133 cm^2

The difference: 32 - 25.133 = 6.867 cm^2 (area of the shaded region)

5 0

3 years ago

What is the difference between the yearly wages of the highest paying job and lowest paying job, assuming Araceli will be paid f

tigry1 [53]

-> 40 hours per week, 52 weeks a year

shop and save grocers

monthly wages: $3,800

hourly wages: $3800 / 160 = $23.75 per hour

yearly wages: $23.75 per hour x 40 hours per week x 52 weeks a year

= $49,400

unbelievable toys

yearly wages: $43,000

convenience store

$16.50 per hour x 40 hours per week x 52 weeks a year

= $34,320

49,400 - 34,320 = 15,080

..? that's not even an answer choice what-

4 0

3 years ago

Find the derivative.

Aleksandr [31]

Answer:

Using either method, we obtain: $t^\frac{3}{8}$

Step-by-step explanation:

a) By evaluating the integral:

$\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du$

The integral itself can be evaluated by writing the root and exponent of the variable u as: $\sqrt[8]{u^3} =u^{\frac{3}{8}$

Then, an antiderivative of this is: $\frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}$

which evaluated between the limits of integration gives:

$\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}$

and now the derivative of this expression with respect to "t" is:

$\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}$

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

$g(x)=\int\limits^x_a {f(t)} \, dt$

is continuous on [a,b], differentiable on (a,b) and $g'(x)=f(x)$

Since this this function $u^{\frac{3}{8}$ is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

$\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}$

5 0

3 years ago

Your company spends 15%of their budget on rent each year. Their operating budget was 45,000 how much was spent

amm1812

You take 45,000 divided by .15= 30,000

30,000 it your answer

Hope this helps

5 0

3 years ago

Read 2 more answers

you want to deposit 15000 in a bank at an interest rate of 7 percent per year. what is the future value of this money after thre

Stolb23 [73]

Approximately about $18,490

PV= $15,000 
FV= solve for 
PMT= 0 
I/YR= 7% 
N= 36 

put these in your HP II calcu and you will get the approximate answer.
- b
e
x
t
e
m
(FAIL HARD)

3 0

3 years ago